{"id":59,"date":"2023-05-30T17:57:52","date_gmt":"2023-05-30T17:57:52","guid":{"rendered":"https:\/\/aceorganicchem.com\/chemistry\/?p=59"},"modified":"2023-05-30T17:57:53","modified_gmt":"2023-05-30T17:57:53","slug":"lewis-structure-of-n2f4-with-video-and-free-study-guide","status":"publish","type":"post","link":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/","title":{"rendered":"Lewis Structure of N2F4 [with video and free study guide]"},"content":{"rendered":"\n<h1 class=\"wp-block-heading\" id=\"h-what-is-the-lewis-structure-of-n2f4\">What is the Lewis Structure of N<sub>2<\/sub>F<sub>4<\/sub>?<\/h1>\n\n\n\n<p>What is the Lewis Structure of N<sub>2<\/sub>F<sub>4<\/sub>?  The Lewis structure has nitrogen as the central atoms, with two fluorine atoms off each nitrogen.  Each fluorine atom has three lone pairs while the nitrogen atoms have one lone pair each. <\/p>\n\n\n\n<h3 class=\"wp-block-heading\">What is this molecule and what is it used for??<\/h3>\n\n\n\n<p> <\/p>\n\n\n\n<p>N<sub>2<\/sub>F<sub>4<\/sub>, also known as dinitrogen tetrafluoride or nitrogen tetrafluoride, is a  highly toxic and reactive chemical compound.  It has several applications including: Rocket propellant, cleaning agent (particularly semiconductors and electronics manufacturing), fluorinating agent (it can be a source of fluorine for chemical reactions), and polymerization initiator (it can start\/catalyze polymerization reactions which are often used in plastics).<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Method 1: Step method to draw the Lewis structure of N<sub>2<\/sub>F<sub>4<\/sub>.<\/h2>\n\n\n\n<p>In this method, we find the bonds and lone pairs for the whole molecule, then plug it in to the atoms that we have to get the answer.  Here is a little flow chart of how we are going to do this:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><a href=\"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/flow-chart-of-step-method.jpg\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/flow-chart-of-step-method.jpg\" alt=\"\" class=\"wp-image-3187\" width=\"633\" height=\"391\"\/><\/a><\/figure>\n\n\n\n<p class=\"has-ast-global-color-8-color has-text-color\">We will go through the steps below, but one thing to note here is that all <strong><em>the valence electrons (step 1) are either lone pairs OR bonding electrons<\/em><\/strong>.  In other words&#8230;. Lone Pairs (Step 5) + Bonding electrons (Step 3) = Valence electrons (Step 1) .  Let&#8217;s go through this example so we can see this a little more clearly. <\/p>\n\n\n\n<p><strong>Step 1<\/strong>: Find valence electrons for all atoms. This is determined by looking at which column on the periodic table the atom is in, ignoring the transition metals in the middle.  Add the valence electrons for each atom together.<br>2N : 2&#215;5 = 10<br>4F : 4&#215;7 = 28<br>Total = <strong>38 valence electrons<\/strong><\/p>\n\n\n\n<p><strong>Step 2<\/strong>: Find octet electrons for each atom and add them together.  Most atoms like 8 electrons to form an octet, but there are exceptions.<\/p>\n\n\n\n<p>2N:  2&#215;8 = 16<br>4F:  4&#215;8 = 32<br>Total = <strong>48 &#8220;octet&#8221; electrons<\/strong><\/p>\n\n\n\n<p><strong>Step 3<\/strong>: Find the number of bonding electrons. Subtract the valence electrons (step 1) from the octet electrons (step 2). This gives the number of bonding electrons. <br>48-38=<strong><em>10 bonding electrons.<\/em><\/strong><\/p>\n\n\n\n<p><strong>Step 4<\/strong>: Find number of bonds by diving the number of bonding electrons (step 3) by 2 because each bond is made of 2 e-<br>10 bonding electrons\/2 = <strong><em>5 bond pairs<\/em><\/strong> <\/p>\n\n\n\n<p><strong>Step 5<\/strong>: Find the number of nonbonding (lone pairs) electrons. Subtract bonding electrons (step 3) number from valence electrons (step 1).<br>38 valence -10 bonding = <strong>28 electrons = <em>14 lone pair<\/em><\/strong><\/p>\n\n\n\n<p>Now, use the information from step 4 and 5 to draw the Lewis structures. Remembering too (this is important):<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">Uncharged nitrogen likes 3 bonds and 1 lone pair<\/p>\n\n\n\n<p class=\"has-vivid-red-color has-text-color\">Fluorine has one bond and three lone pairs<\/p>\n\n\n\n<p><em>[Note: For more information on the <a href=\"https:\/\/www.aceorganicchem.com\/blog\/know-the-normal-state-for-common-organic-atoms\/\" target=\"_blank\" rel=\"noreferrer noopener\">natural state of common atoms<\/a>, see the linked post here.] <\/em><\/p>\n\n\n\n<p>The N atoms will be our central atoms because it is the most electropositive.  We then place the fluorine atoms around them, creating one bond to each F atom. <strong><em> [Hint: Nature loves symmetry, so it is always a good idea to start with a symmetrical molecule and see if that works first!]<\/em><\/strong> Behold, N<sub>2<\/sub>F<sub>4<\/sub> Lewis dot structure. <\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><a href=\"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/N2F4-lewis-structure.jpg\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/N2F4-lewis-structure-1024x566.jpg\" alt=\"Lewis Structure of N2F4\" class=\"wp-image-3221\" width=\"664\" height=\"367\"\/><\/a><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-another-easier-method-to-determine-the-lewis-structure-of-n2f4\">Another (easier) method to determine the Lewis structure of N<sub>2<\/sub>F<sub>4<\/sub>:<\/h2>\n\n\n\n<p>Alternatively a dot method can be used to draw the Lewis structure.<br>Calculate the total valence electrons in the molecule.<br>2N : 2&#215;5 = 10<br>4F : 4&#215;7 = 28<br>Total = <strong>38 valence electrons<\/strong><\/p>\n\n\n\n<p>Now, treat the atoms and electrons like puzzle pieces.  Put the two nitrogen atoms in the center and arrange the fluorine atoms on the sides. Remember the natural state of each atom, as discussed above. <strong>[F: 1 bonds, 3 LP;  N: 3 bonds, 1 LP; ]<\/strong> Also, make sure sure each atom has an octet. Behold, the Lewis Structure of N<sub>2<\/sub>F<sub>4<\/sub>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><a href=\"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/N2F4-puzzle-.jpg\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/N2F4-puzzle--1024x580.jpg\" alt=\"Lewis Structure of N2F4\" class=\"wp-image-3222\" width=\"604\" height=\"342\"\/><\/a><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-frequently-asked-questions\">Frequently asked questions:<\/h2>\n\n\n\n<p>Q: So what is the difference between the two methods?<\/p>\n\n\n\n<p>A: In the first method, we are figuring out all of the lone pairs and bonds first, then placing those electrons and bonds on the atoms to form a molecule.  In the puzzle method, we already have lone pairs and bonding electrons assigned to each atom, so all we need to do is push puzzle pieces together to get a molecule.  In each method, we need to remember the &#8220;happy state&#8221; of each atom, ei hydrogen likes 1 bond and no lone pairs, uncharged carbon likes four bonds and no lone pairs ect. <\/p>\n\n\n\n<p>Q: Just by looking at the molecule, are there clues it might be unstable?<\/p>\n\n\n\n<p>A:  Excellent question!  Yes, there are.  Your first clue is nitrogen single-bonded to another nitrogen.  This is highly unstable because the lone pairs on the N are so close to each other, and because there are so many other lone pairs on the molecule, it can rotate to a lower energy configuration.<\/p>\n\n\n\n<p>And now some video:<\/p>\n\n\n\n<p>This is a quick video we put together that visually demonstrates the two methods for Lewis structure and Lewis dot problems. <\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<div class=\"ast-oembed-container \" style=\"height: 100%;\"><iframe loading=\"lazy\" title=\"How to create Lewis dots representations using two different methods\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/KQUJfL-V7TM?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe><\/div>\n<\/div><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-and-finally-the-lewis-structure-study-guide\">And finally, the Lewis structure study guide:<\/h2>\n\n\n\n<p>Here it is, this is our one-page guide to Lewis Dot and Lewis Structures:<\/p>\n\n\n\n<p><a href=\"https:\/\/www.aceorganicchem.com\/Lewis-Dot-Structure-guide.pdf\" target=\"_blank\" rel=\"noreferrer noopener\">Lewis structure study guide<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the Lewis Structure of N2F4? What is the Lewis Structure of N2F4? The Lewis structure has nitrogen as the central atoms, with two fluorine atoms off each nitrogen. Each fluorine atom has three lone pairs while the nitrogen atoms have one lone pair each. What is this molecule and what is it used [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"disabled","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"var(--ast-global-color-4)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""}},"footnotes":""},"categories":[1],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v24.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Lewis Structure of N2F4 [with video and free study guide]<\/title>\n<meta name=\"description\" content=\"We show two methods to find correct Lewis Structure of N2F4. 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There is also a video and a study guide to help with other Lewis dot problems.","og_url":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/","og_site_name":"General chemistry help is here","article_published_time":"2023-05-30T17:57:52+00:00","article_modified_time":"2023-05-30T17:57:53+00:00","og_image":[{"url":"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/flow-chart-of-step-method.jpg","type":"","width":"","height":""}],"author":"genchem","twitter_card":"summary_large_image","twitter_misc":{"Written by":"genchem","Est. reading time":"5 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/#article","isPartOf":{"@id":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/"},"author":{"name":"genchem","@id":"https:\/\/aceorganicchem.com\/chemistry\/#\/schema\/person\/84511d00da7e9acfd3b22eea4d21d5de"},"headline":"Lewis Structure of N2F4 [with video and free study guide]","datePublished":"2023-05-30T17:57:52+00:00","dateModified":"2023-05-30T17:57:53+00:00","mainEntityOfPage":{"@id":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/"},"wordCount":813,"commentCount":0,"publisher":{"@id":"https:\/\/aceorganicchem.com\/chemistry\/#organization"},"image":{"@id":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/#primaryimage"},"thumbnailUrl":"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/flow-chart-of-step-method.jpg","inLanguage":"en-US","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/","url":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/","name":"Lewis Structure of N2F4 [with video and free study guide]","isPartOf":{"@id":"https:\/\/aceorganicchem.com\/chemistry\/#website"},"primaryImageOfPage":{"@id":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/#primaryimage"},"image":{"@id":"https:\/\/aceorganicchem.com\/chemistry\/lewis-structure-of-n2f4-with-video-and-free-study-guide\/#primaryimage"},"thumbnailUrl":"https:\/\/www.aceorganicchem.com\/blog\/wp-content\/uploads\/2023\/05\/flow-chart-of-step-method.jpg","datePublished":"2023-05-30T17:57:52+00:00","dateModified":"2023-05-30T17:57:53+00:00","description":"We show two methods to find correct Lewis Structure of N2F4. One uses math, the other \"puzzle pieces\" to give the three correct structure. 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His research focus was on novel pain killers which were more potent than morphine but designed to have fewer side effects. Prior to all of this, he was a chemist at Procter and Gamble. After all of that, he (briefly) worked as a post-doctoral assistant at Syracuse University, working on novel organic light-emitting diodes (OLEDs). In between, he did NOT compete at the 1996 Olympics, make the Atlanta Braves opening day roster, or become the head coach of the Indiana Pacers, as he had intended. #fail During this entire time, he always loved helping students, especially if they were struggling with organic chemistry.","sameAs":["http:\/\/aceorganicchem.com\/chemistry"],"url":"https:\/\/aceorganicchem.com\/chemistry\/author\/genchem\/"}]}},"_links":{"self":[{"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/posts\/59"}],"collection":[{"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/comments?post=59"}],"version-history":[{"count":1,"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/posts\/59\/revisions"}],"predecessor-version":[{"id":60,"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/posts\/59\/revisions\/60"}],"wp:attachment":[{"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/media?parent=59"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/categories?post=59"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/aceorganicchem.com\/chemistry\/wp-json\/wp\/v2\/tags?post=59"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}